总功率为215kw的设备距离300米用多大电缆?
215kW/1.732/0.38/0.8 = 408.3A(额定电流),10/408.3 =0.0245Ω(300 m电缆的最大电阻值)用传统最大型号计算:300 m 240 mm 240 mm 240 mm2铝电缆:28.3/240 *0.3/240 *0.3/240 *0.3/ = 0.03544 = 0.03544 = 0.03544 = 0.03544 = 0.03544 = 0.03544 = 0.03544 = 0.03544 = 0.03544 = 0.0354 = 0.03544 = 0.03544 = 0.03544454 = 0.03544 = 0.0354 = 0.03544 = 0.03544 = 0.0354 = 0.03544 0. 可以使用两根铜电缆。有两个185 mm2 370 mm 2,28.3/370*0.3 =0.023Ω,10/0.023 = 434.8a(最大负载量)。